You can try to get as much of the string to be in contact with the ice as possible. Might be start off a water that's a bit cooler. Trial and error a few times?
If that still doesn't work, I think after you have left the string in contact with the ice for a minute or two, you can dip more string into the water to wet it and place the wet string on the string already on the ice. This will help to dilute the salt water on the top of the ice more?
OK, if using additional substances is not cheating, then put some superglue on the table and then stick the egg to it 😀
Seriously, I am certain someone will come up with a proper method.
Yes, that's the official answer. But not quite true of course as the poor can have many things that money can't buy. The rich crave for many things also. You can live connected to a drip without eating anything...
It does work. Here is a video to prove it.
I think the reason is as follows. The salt helps the ice to melt. Once some salt water is generated, it get diluted by the water already in the glass. The ice itself can be very cold, say -15 degrees and cause the water surrounding the string to refreeze.
I am not totally certain as I have not tried this before. Ice melts more easily as you put pressure on it. Hence the string can cut into the ice. Although the ambient temperature is more than zero degrees, the ice itself can still be -10 degrees. Hence, the water on top of the string will refreeze.
Just a thought. No coin fairs, no room bidding in auctions, less lots being assigned etc. Will there simply be much less new stock on the market in the next 6 months?
Yes, I too realised the angle would be an additional variable. The first idea to come to mind is to express sin (angle) in terms of length and radius. But then it will get messy and rearranging to get the ratio of length/radius might be difficult or not feasible.
I was thinking of doing it by a different way. The area of sector + the areas of the 2 segments. Rather curious if we can still remember the A level maths done decades ago. But on second thought, I would rather make some lunch instead.
I am not certain I follow you. You pick a random robot and ask "Which door would the other robot say is the safe door?" If you have picked the truth telling robot, he will point to the death door (assuming he knows the other robot always lies). If you picked the lying robot, then he would also point to the death door (because he knows that the truth telling robot would point to the safe door and so he lies and point to the death door). Either way you go through the other door.